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9x=3x^2+12
We move all terms to the left:
9x-(3x^2+12)=0
We get rid of parentheses
-3x^2+9x-12=0
a = -3; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·(-3)·(-12)
Δ = -63
Delta is less than zero, so there is no solution for the equation
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